(2(2^0.5)^0.5)/2^0.5+4=y/2^0.5

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Solution for (2(2^0.5)^0.5)/2^0.5+4=y/2^0.5 equation: 


D( y )

2^0.5 = 0

2^0.5 < 0

2^0.5 = 0

2^0.5 = 0

2^0.5 = 0

y belongs to the empty set

2^0.5 < 0

2^0.5 < 0

2^0.5 < 0

y belongs to the empty set

y in (-oo:+oo)

(2*(2^0.5)^0.5)/(2^0.5)+4 = y/(2^0.5) // - y/(2^0.5)

(2*(2^0.5)^0.5)/(2^0.5)-(y/(2^0.5))+4 = 0

2*2^-0.25-2^-0.5*y+4 = 0 // - 2*2^-0.25+4

-2^-0.5*y = -(2*2^-0.25+4) // : -2^-0.5

y = (-(2*2^-0.25+4))/(-2^-0.5)

y = (2*2^-0.25+4)/(2^-0.5)

y = (2*2^-0.25+4)/(2^-0.5)

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